Question
Answer
$$(13-3i)\cdot(2-8i)=24i^2-110i+26$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(13-3i)\cdot(2-8i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}26-104i-6i+24i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}24i^2-110i+26\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{13-3i}\right) $ by each term in $ \left( 2-8i\right) $. $$ \left( \color{blue}{13-3i}\right) \cdot \left( 2-8i\right) = 26-104i-6i+24i^2 $$ |
| ② | Combine like terms: $$ 26 \color{blue}{-104i} \color{blue}{-6i} +24i^2 = 24i^2 \color{blue}{-110i} +26 $$ |
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