Question
Answer
$$(11-9i)\cdot(2-3i)=27i^2-51i+22$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(11-9i)\cdot(2-3i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}22-33i-18i+27i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}27i^2-51i+22\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{11-9i}\right) $ by each term in $ \left( 2-3i\right) $. $$ \left( \color{blue}{11-9i}\right) \cdot \left( 2-3i\right) = 22-33i-18i+27i^2 $$ |
| ② | Combine like terms: $$ 22 \color{blue}{-33i} \color{blue}{-18i} +27i^2 = 27i^2 \color{blue}{-51i} +22 $$ |
This page was created using
Complex Expression calculator