Question
Answer
$$\dfrac{11-2i}{25}+\dfrac{-5-10i}{25}=\dfrac{-12i+6}{25}$$
Explanation
| $$ \begin{aligned}\frac{11-2i}{25}+\frac{-5-10i}{25}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{-12i+6}{25}\end{aligned} $$ | |
| ① | Add $ \dfrac{11-2i}{25} $ and $ \dfrac{-5-10i}{25} $ to get $ \dfrac{-12i+6}{25} $. To add expressions with the same denominators, we add the numerators and write the result over the common denominator. $$ \begin{aligned} \frac{11-2i}{25} + \frac{-5-10i}{25} & = \frac{11-2i}{\color{blue}{25}} + \frac{-5-10i}{\color{blue}{25}} = \\[1ex] &=\frac{ 11-2i + \left( -5-10i \right) }{ \color{blue}{ 25 }}= \frac{-12i+6}{25} \end{aligned} $$ |
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