Question
Answer
$$\dfrac{10+iw}{iw(-w^2+3iw+50)}=\dfrac{10+iw}{-iw^3+3i^2w^2+50iw}$$
Explanation
| $$ \begin{aligned}\frac{10+iw}{iw(-w^2+3iw+50)}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{10+iw}{-iw^3+3i^2w^2+50iw}\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{iw} $ by $ \left( -w^2+3iw+50\right) $ $$ \color{blue}{iw} \cdot \left( -w^2+3iw+50\right) = -iw^3+3i^2w^2+50iw $$ |
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