Question
Answer
$$(1-6xi)^2=36i^2x^2-12ix+1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(1-6xi)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}1-12ix+36i^2x^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}36i^2x^2-12ix+1\end{aligned} $$ | |
| ① | Find $ \left(1-6ix\right)^2 $ using formula. $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 1 } $ and $ B = \color{red}{ 6ix }$. $$ \begin{aligned}\left(1-6ix\right)^2 = \color{blue}{1^2} -2 \cdot 1 \cdot 6ix + \color{red}{\left( 6ix \right)^2} = 1-12ix+36i^2x^2\end{aligned} $$ |
| ② | Combine like terms: $$ 36i^2x^2-12ix+1 = 36i^2x^2-12ix+1 $$ |
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