Question
Answer
$$(1-3i)i^0+(1+3i)(-i^0)=-6i$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(1-3i)i^0+(1+3i)(-i^0)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}1-3i-1-3i \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-6i\end{aligned} $$ | |
| ① | $$ \left( \color{blue}{1-3i}\right) \cdot 1 = 1-3i $$$$ \left( \color{blue}{1+3i}\right) \cdot -1 = -1-3i $$ |
| ② | Combine like terms: $$ \, \color{blue}{ \cancel{1}} \, \color{green}{-3i} \, \color{blue}{ -\cancel{1}} \, \color{green}{-3i} = \color{green}{-6i} $$ |
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