Question
Answer
$$(0.092-j\cdot0.026)e^{-(3+jv\cdot2)t}=(0.092-0j)e^{-3t-2jtv}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(0.092-j\cdot0.026)e^{-(3+jv\cdot2)t}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(0.092-0j)e^{-(3t+2jtv)} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}(0.092-0j)e^{-3t-2jtv}\end{aligned} $$ | |
| ① | $$ \left( \color{blue}{3+2jv}\right) \cdot t = 3t+2jtv $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(3t+2jtv \right) = -3t-2jtv $$ |
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