Question
Answer
$$(-8i)\cdot(-8+6i)=64i+48$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(-8i)\cdot(-8+6i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}64i-48i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}64i+48\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{-8i} $ by $ \left( -8+6i\right) $ $$ \color{blue}{-8i} \cdot \left( -8+6i\right) = 64i-48i^2 $$ |
| ② | $$ -48i^2 = -48 \cdot (-1) = 48 $$ |
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