Question
Answer
$$(-6i-6)(2i+6)=-12i^2-48i-36$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(-6i-6)(2i+6)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-12i^2-36i-12i-36 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-12i^2-48i-36\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{-6i-6}\right) $ by each term in $ \left( 2i+6\right) $. $$ \left( \color{blue}{-6i-6}\right) \cdot \left( 2i+6\right) = -12i^2-36i-12i-36 $$ |
| ② | Combine like terms: $$ -12i^2 \color{blue}{-36i} \color{blue}{-12i} -36 = -12i^2 \color{blue}{-48i} -36 $$ |
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