Question
Answer
$$(-3+j)\cdot(-1+2j)=2j^2-7j+3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(-3+j)\cdot(-1+2j)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3-6j-j+2j^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2j^2-7j+3\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{-3+j}\right) $ by each term in $ \left( -1+2j\right) $. $$ \left( \color{blue}{-3+j}\right) \cdot \left( -1+2j\right) = 3-6j-j+2j^2 $$ |
| ② | Combine like terms: $$ 3 \color{blue}{-6j} \color{blue}{-j} +2j^2 = 2j^2 \color{blue}{-7j} +3 $$ |
This page was created using
Complex Expression calculator