Question
Answer
$$(-3-2i)(-3i-4)=6i^2+17i+12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(-3-2i)(-3i-4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}9i+12+6i^2+8i \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6i^2+17i+12\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{-3-2i}\right) $ by each term in $ \left( -3i-4\right) $. $$ \left( \color{blue}{-3-2i}\right) \cdot \left( -3i-4\right) = 9i+12+6i^2+8i $$ |
| ② | Combine like terms: $$ \color{blue}{9i} +12+6i^2+ \color{blue}{8i} = 6i^2+ \color{blue}{17i} +12 $$ |
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