Question
Answer
$$\dfrac{-2j+6}{j(-2j-2)}=\dfrac{-j+3}{-j^2-j}$$
Explanation
| $$ \begin{aligned}\frac{-2j+6}{j(-2j-2)}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{-2j+6}{-2j^2-2j} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{-j+3}{-j^2-j}\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{j} $ by $ \left( -2j-2\right) $ $$ \color{blue}{j} \cdot \left( -2j-2\right) = -2j^2-2j $$ |
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