Question
Answer
$$(-2i)^3\cdot(-2)=-16i$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(-2i)^3\cdot(-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-8i^3\cdot(-2) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}16i^3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-16i\end{aligned} $$ | |
| ① | $$ \left( -2i \right)^3 = (-2)^3i^3 = -8i^3 $$ |
| ② | $$ -8 i^3 \cdot -2 = 16 i^{3} $$ |
| ③ | $$ 16i^3 = 16 \cdot \color{blue}{i^2} \cdot i =
16 \cdot ( \color{blue}{-1}) \cdot i =
-16 \cdot \, i $$ |
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