Question
Answer
$$(-2-2i)(8i+4)=-16i^2-24i-8$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(-2-2i)(8i+4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-16i-8-16i^2-8i \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-16i^2-24i-8\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{-2-2i}\right) $ by each term in $ \left( 8i+4\right) $. $$ \left( \color{blue}{-2-2i}\right) \cdot \left( 8i+4\right) = -16i-8-16i^2-8i $$ |
| ② | Combine like terms: $$ \color{blue}{-16i} -8-16i^2 \color{blue}{-8i} = -16i^2 \color{blue}{-24i} -8 $$ |
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