Question
Answer
$$(-1+4i)\cdot(4-3i)=-12i^2+19i-4$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(-1+4i)\cdot(4-3i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-4+3i+16i-12i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-12i^2+19i-4\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{-1+4i}\right) $ by each term in $ \left( 4-3i\right) $. $$ \left( \color{blue}{-1+4i}\right) \cdot \left( 4-3i\right) = -4+3i+16i-12i^2 $$ |
| ② | Combine like terms: $$ -4+ \color{blue}{3i} + \color{blue}{16i} -12i^2 = -12i^2+ \color{blue}{19i} -4 $$ |
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