Question
Answer
$$(-14i+1)(2i-7)=-28i^2+100i-7$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(-14i+1)(2i-7)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-28i^2+98i+2i-7 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-28i^2+100i-7\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{-14i+1}\right) $ by each term in $ \left( 2i-7\right) $. $$ \left( \color{blue}{-14i+1}\right) \cdot \left( 2i-7\right) = -28i^2+98i+2i-7 $$ |
| ② | Combine like terms: $$ -28i^2+ \color{blue}{98i} + \color{blue}{2i} -7 = -28i^2+ \color{blue}{100i} -7 $$ |
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