Question
Answer
$$\dfrac{-1-8j}{4j\cdot(1+2j)}=\dfrac{-1-8j}{4j+8j^2}$$
Explanation
| $$ \begin{aligned}\frac{-1-8j}{4j\cdot(1+2j)}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{-1-8j}{4j+8j^2}\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{4j} $ by $ \left( 1+2j\right) $ $$ \color{blue}{4j} \cdot \left( 1+2j\right) = 4j+8j^2 $$ |
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