Question
Answer
$$(-0.0368+0.1025i)i\cdot2pi\cdot70\cdot0.1=0$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(-0.0368+0.1025i)i\cdot2pi\cdot70\cdot0.1& \xlongequal{ }(-0.0368+0i)i\cdot2pi\cdot70\cdot0.1 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(0i+0i^2)\cdot2pi\cdot70\cdot0.1 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}(0i+0i^2)pi\cdot70\cdot0.1 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}(0ip+0i^2p)i\cdot70\cdot0.1 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}(0i^2p+0i^3p)\cdot70\cdot0.1 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle5}{\textcircled {5}} } }}}(0i^2p+0i^3p)\cdot0.1 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle6}{\textcircled {6}} } }}}0i^2p+0i^3p \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle7}{\textcircled {7}} } }}}0\end{aligned} $$ | |
| ① | $$ \left( \color{blue}{00i}\right) \cdot i = 0i0i^2 $$ |
| ② | $$ \left( \color{blue}{0i0i^2}\right) \cdot 2 = 0i0i^2 $$ |
| ③ | $$ \left( \color{blue}{0i0i^2}\right) \cdot p = 0ip0i^2p $$ |
| ④ | $$ \left( \color{blue}{0ip0i^2p}\right) \cdot i = 0i^2p0i^3p $$ |
| ⑤ | $$ \left( \color{blue}{0i^2p0i^3p}\right) \cdot 70 = 0i^2p0i^3p $$ |
| ⑥ | $$ \left( \color{blue}{0i^2p0i^3p}\right) \cdot 0 = 0i^2p0i^3p $$ |
| ⑦ | Combine like terms: $$ 0 = 0 $$ |
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