Question
Answer
$$\dfrac{(z-2)\cdot(1-i)}{z+2}=\dfrac{z-iz-2+2i}{z+2}$$
Explanation
| $$ \begin{aligned}\frac{(z-2)\cdot(1-i)}{z+2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{z-iz-2+2i}{z+2}\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{z-2}\right) $ by each term in $ \left( 1-i\right) $. $$ \left( \color{blue}{z-2}\right) \cdot \left( 1-i\right) = z-iz-2+2i $$ |
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