Question
Answer
$$((x+iy)^2-2)e^{-x}e^{-iy}=(x^2+2ixy+i^2y^2-2)e^{-x}e^{-iy}$$
Explanation
| $$ \begin{aligned}((x+iy)^2-2)e^{-x}e^{-iy}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(x^2+2ixy+i^2y^2-2)e^{-x}e^{-iy}\end{aligned} $$ | |
| ① | Find $ \left(x+iy\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ x } $ and $ B = \color{red}{ iy }$. $$ \begin{aligned}\left(x+iy\right)^2 = \color{blue}{x^2} +2 \cdot x \cdot iy + \color{red}{\left( iy \right)^2} = x^2+2ixy+i^2y^2\end{aligned} $$ |
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