Question
Answer
$$\dfrac{(a+il)(-ic)}{a+il-ic}=\dfrac{-aci-ci^2l}{a+il-ic}$$
Explanation
| $$ \begin{aligned}\frac{(a+il)(-ic)}{a+il-ic}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{-aci-ci^2l}{a+il-ic}\end{aligned} $$ | |
| ① | $$ \left( \color{blue}{a+il}\right) \cdot -ci = -aci-ci^2l $$ |
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