Question
Answer
$$\dfrac{(13-5i)\cdot10}{13-5i+10}=\dfrac{1620-250i}{277}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{(13-5i)\cdot10}{13-5i+10}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{130-50i}{-5i+23} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{1620-250i}{277}\end{aligned} $$ | |
| ① | $$ \left( \color{blue}{13-5i}\right) \cdot 10 = 130-50i $$ |
| ② | Combine like terms: $$ \color{blue}{13} -5i+ \color{blue}{10} = -5i+ \color{blue}{23} $$ |
| ③ | Divide $ \, 130-50i \, $ by $ \, 23-5i \, $ to get $\,\, \dfrac{1620-250i}{277} $. ( view steps ) |
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