The center of the circle is point: $ C = \left(-1, -1\right) $.
The radius of the circle is $ r = 2 $.
Step 1: Group x and y terms together, move the number to the right side.
$$ x^2 + 2 x + y^2 + 2 y = 2 $$Step 2: Write the equation in the following form.
$$ \left( x^2 + 2 x + \color{blue}{\spadesuit} \right) + \left( y^2 + 2 y + \color{red}{\clubsuit} \right) = 2 + \color{blue}{\spadesuit} + \color{red}{\clubsuit} $$( the symbols $ \color{blue}{\spadesuit} $ and $ \color{red}{\clubsuit} $ , are the number needed to complete the square )
Step 3: To find $\color{blue}{\spadesuit}$ , take the x - term, divide it by 2 an then square the result. In this example we have:
$$ \color{blue}{\spadesuit} = \left( \frac{ 2 }{2} \right)^2 = 1 $$Step 4: To find $\color{red}{\clubsuit}$ , take the y - term, divide it by 2 an then square the result.
$$ \color{red}{\clubsuit} = \left( \frac{ 2 }{2} \right)^2 = 1 $$Step 5: Put steps 2, 3 and 4 together.
$$ \begin{aligned} \left( x^2 + 2 x + \color{blue}{ 1 } \right) + \left( y^2 + 2 y + \color{red}{ 1 }\right) &= 2 + \color{blue}{ 1 } + \color{red}{ 1 } \\ \left( x^2 + 2 x + 1 \right) + \left( y^2 + 2 y + 1 \right) &= 4 \\ \left( x + 1 \right)^2 + \left( y + 1 \right)^2 &= 4 \end{aligned}$$Step 6: Read off the answer from the last equation. (note that $ r^2 = 4 $ so $ r = \sqrt{ 4 } = 2 $).