Question
Find the sum of the vectors $ \vec{v_1} = \left(-\dfrac{ 2 }{ 5 },~\dfrac{ 3 }{ 5 }\right) $ and $ \vec{v_2} = \left(5,~29\right) $ .
Answer
$$ v_1 + v_2 = \left(\dfrac{ 23 }{ 5 },~\dfrac{ 148 }{ 5 }\right) $$
Explanation
To find the sum $ v $ of the vectors $ v_1=(a_1, b_1) $ and $ v_2=(a_2, b_2) $ we use formula
$$ v = (a_1 + a_2, b_1 + b_2) $$In this example $ a_1 = -\frac{ 2 }{ 5 } $ , $ b_1 = \frac{ 3 }{ 5 } $, $ a_2 = 5 $ and $ b_2 = 29 $, therefore:
$$ \begin{aligned}v &= (a_1 + a_2, b_1 + b_2) \\v &= \left(-\frac{ 2 }{ 5 } + 5, \frac{ 3 }{ 5 } + 29 \right) \\v &= \left(\dfrac{ 23 }{ 5 },~\dfrac{ 148 }{ 5 }\right) \end{aligned} $$This page was created using
Vectors Calculator