Question
Find the difference of the vectors $ \vec{v_1} = \left(4,~6\right) $ and $ \vec{v_2} = \left(5,~2\right) $ .
Answer
$$ v_1 - v_2 = \left(-1,~4\right) $$
Explanation
To find the difference $ v $ of the vectors $ v_1=(a_1, b_1) $ and $ v_2=(a_2, b_2) $ we use formula
$$ v = (a_1 - a_2, b_1 - b_2) $$In this example $ a_1 = 4 $ , $ b_1 = 6 $, $ a_2 = 5 $ and $ b_2 = 2 $, therefore:
$$ \begin{aligned}v &= (a_1 - a_2, b_1 - b_2) \\v &= \left(4 - 5, 6 - 2 \right) \\v &= \left(-1,~4\right) \end{aligned} $$This page was created using
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