The equation of the line passing through point $ \left(4,~5\right) $, and point $ \left(9,~2\right) $ is:
$$ 3x+5y-37=0 $$To find equation of the line passing through points $ A(x_A,y_A) $ and $ B(x_B,y_B) $, we use formula:
$$ y - y_A~=~\frac{y_B - y_A}{x_B - x_A}(x-x_A) $$In this example we have:
$$ \begin{aligned} & \left(4,~5\right) \implies x_A = 4 ~~\text{and}~~ y_A = 5 \\[1 em] & \left(9,~2\right) \implies x_B = 9 ~~\text{and}~~ y_B = 2 \end{aligned} $$After substituting into the formula, we obtain:
$$ \begin{aligned} y - y_A~&=~\frac{y_B - y_A}{x_B - x_A}(x - x_A) \\[1 em] y - 5~&=~\frac{ 2 - 5 }{ 9 - 4 } \left( x - 4 \right) \\[1 em]y - 5 ~&=~ -\frac{ 3 }{ 5 } \left( x - 4 \right) \\[1 em]y - 5 ~&=~ -\frac{ 3 }{ 5 }x + \frac{ 12 }{ 5 } \\[1 em]y ~&=~ -\frac{ 3 }{ 5 }x + \frac{ 37 }{ 5 } \end{aligned} $$