The equation of the line passing through point $ \left(0,~15\right) $, and point $ \left(\dfrac{ 27 }{ 2 },~14.25\right) $ is:
$$ x+18y-270=0 $$To find equation of the line passing through points $ A(x_A,y_A) $ and $ B(x_B,y_B) $, we use formula:
$$ y - y_A~=~\frac{y_B - y_A}{x_B - x_A}(x-x_A) $$In this example we have:
$$ \begin{aligned} & \left(0,~15\right) \implies x_A = 0 ~~\text{and}~~ y_A = 15 \\[1 em] & \left(\dfrac{ 27 }{ 2 },~14.25\right) \implies x_B = \frac{ 27 }{ 2 } ~~\text{and}~~ y_B = 14.25 \end{aligned} $$After substituting into the formula, we obtain:
$$ \begin{aligned} y - y_A~&=~\frac{y_B - y_A}{x_B - x_A}(x - x_A) \\[1 em] y - 15~&=~\frac{ 14.25 - 15 }{ \frac{ 27 }{ 2 } - 0 } \left( x - 0 \right) \\[1 em]y - 15 ~&=~ -0.0556 \left( x - 0 \right) \\[1 em]y - 15 ~&=~ -0.0556x + 0 \\[1 em]y ~&=~ -0.0556x + 15 \end{aligned} $$