Question
Find the medians of triangle $\left(-\dfrac{ 3 }{ 2 },~0\right)$ $\left(\dfrac{ 3 }{ 2 },~0\right)$ $\left(0,~2.598\right)$.
Answer
The lengths of the medians of a triangle $ ABC $ are:
$$ m_a = 2.5981 ~~,~~ m_b = 2.5981 ~~,~~ m_c = 2.598 $$Explanation
A median $ m_a $ is a line segment joining a vertex $ A $ to the midpoint of the side $ BC $. In this example the midpoint of $ BC $ is $ \left(\dfrac{ 3 }{ 4 },~1.299\right) $.
The distance between $ A $ and $ M $ is:
$$ d(A,M) = 2.5981 $$This page was created using
Triangle Calculator