Step 1: Keep all terms containing $ x $ on one side. Move $ -2 $ to the right.

$$ x^2+2x = 2 $$

Step 2: Take half of the x -term coefficient and square it. Add this value to both sides.

The x-term coefficient = $ 2 $

The half of the x-term coefficient = $ 1 $

After squaring we have $ 1^2 = 1 $

When we add $ 1 $ to both sides we have:

$$ x^2+2x+1 = 2 + 1 $$

Step 3: Simplify right side.

$$ x^2+2x+1 = 3 $$

Step 4: Write the perfect square on the left.

$$ \left(x + 1 \right)^2 = 3 $$

Step 5: Take the square root of both sides.

$$ x + 1 = \pm \sqrt { 3 } $$

Step 6: Solve for $ x $.

$ x_1,x_2 = - 1 \pm \sqrt{ 3 } $

that is,

$ x_1 = -1-\sqrt{ 3 } $

$ x_2 = -1+\sqrt{ 3 } $

Quadratic Equation Solver