The distance from the point $ (x_0, y_0) $ to the line $ Ax + By + C = 0 $ is given by:

$$ d = \frac{ \left| Ax_0 + B_yo + C \right| }{ \sqrt{A^2 + B^2}} $$

After substituting: $ A = 4 $ , $ B = -3 $ , $ C = -5 $ , $ x_0 = 1 $ and $ y_0 = 3 $ we have:

$$ \begin{aligned} d =& \frac{ \left| 4\cdot1 +\left(-3\right)\cdot3 + \left( -5\right) \right| }{\sqrt{ 4^2 + (-3)^2}} = \\ d =& \frac{ \left| 4 -9 -5 \right| }{\sqrt{ 16 + 9}} = \\ d =& \frac{ \left| -10 \right| }{\sqrt{ 25}} = \\ d =& \frac{ 10 }{ 5 } = \\ d =& 2 \end{aligned} $$

Line-point distance calculator