The distance from the point $ (x_0, y_0) $ to the line $ Ax + By + C = 0 $ is given by:

$$ d = \frac{ \left| Ax_0 + B_yo + C \right| }{ \sqrt{A^2 + B^2}} $$

To apply this formula, we first need to express the line in standard form

$$\begin{aligned} y & = 1.732 x + 0.2679 \\x-0.5774y+0.1547&=0\end{aligned}$$

After substituting: $ A = 1 $ , $ B = -0.5774 $ , $ C = 0.1547 $ , $ x_0 = 4 $ and $ y_0 = 3 $ we have:

$$ \begin{aligned} d =& \frac{ \left| 1\cdot4 +\left(-0.5774\right)\cdot3 + 0.1547 \right| }{\sqrt{ 1^2 + (-0.5774)^2}} = \\ d =& \frac{ \left| 4 -1.7321 + 0.1547 \right| }{\sqrt{ 1 + 0.3334}} = \\ d =& \frac{ \left| 2.4226 \right| }{\sqrt{ 1.3334}} = \\ d =& \frac{ 2.4226 }{ 1.1547 } = \\ d =& 2.098 \end{aligned} $$

Line-point distance calculator