The distance from the point $ (x_0, y_0) $ to the line $ Ax + By + C = 0 $ is given by:

$$ d = \frac{ \left| Ax_0 + B_yo + C \right| }{ \sqrt{A^2 + B^2}} $$

To apply this formula, we first need to express the line in standard form

$$\begin{aligned} y & = 1.5046 x + 16.7308 \\x-0.6646y+11.1198&=0\end{aligned}$$

After substituting: $ A = 1 $ , $ B = -0.6646 $ , $ C = 11.1198 $ , $ x_0 = -0.09 $ and $ y_0 = 14.26 $ we have:

$$ \begin{aligned} d =& \frac{ \left| 1\cdot\left(-0.09\right) +\left(-0.6646\right)\cdot14.26 + 11.1198 \right| }{\sqrt{ 1^2 + (-0.6646)^2}} = \\ d =& \frac{ \left| -0.09 -9.4776 + 11.1198 \right| }{\sqrt{ 1 + 0.4417}} = \\ d =& \frac{ \left| 1.5522 \right| }{\sqrt{ 1.4417}} = \\ d =& \frac{ 1.5522 }{ 1.2007 } = \\ d =& 1.2927 \end{aligned} $$

Line-point distance calculator