Question
Find eigenvectors of matrix:
$$ A = \left[ \begin{matrix}8&-3&-3\\0&5&-3\\0&-9&-1\end{matrix} \right] $$Answer
The eigenvectors and eigenvalues of matrix A are:
| Eigenvalue | Eigenvector |
| $ -4 $ | $ \begin{bmatrix} 1 \cr 1 \cr 3 \end{bmatrix} $ |
| $ 8 $ | $ \begin{bmatrix} 1 \cr 0 \cr 0 \end{bmatrix} $ |
| $ 8 $ | $ \begin{bmatrix} 0 \cr 1 \cr -1 \end{bmatrix} $ |
Explanation
Step 1 : Find characteristic polynomial $ p(\lambda) $:
$$ p(\lambda) = -\lambda^3+12\lambda^2-256 $$Step 2 : Find the eigenvalues by solving the characteristic equation $ -\lambda^3+12\lambda^2-256 = 0. $
The eigenvalues are
$$ \lambda_1 = -4 ~ , ~ \lambda_2 = 8 ~ , ~ \lambda_3 = 8 $$( click here to view an explanation on how to solve this equation.)
Step 3 : To find the associated eigenvectors ( $ x $ ), we have to solve the equation $ A x = \lambda I $.
For $ \lambda_ 0 = -4 $ we have $ A x = -4 I $.
For $ \lambda_ 1 = 8 $ we have $ A x = 8 I $.
This page was created using
Eigenvectors calculator