Question
Find eigenvectors of matrix:
$$ A = \left[ \begin{matrix}2&-3&0\\1&6&0\\0&0&5\end{matrix} \right] $$Answer
The eigenvectors and eigenvalues of matrix A are:
| Eigenvalue | Eigenvector |
| $ 3 $ | $ \begin{bmatrix} 1 \cr -{{1}\over{3}} \cr 0 \end{bmatrix} $ |
| $ 5 $ | $ \begin{bmatrix} 1 \cr -1 \cr 0 \end{bmatrix} $ |
| $ 5 $ | $ \begin{bmatrix} 0 \cr 0 \cr 1 \end{bmatrix} $ |
Explanation
Step 1 : Find characteristic polynomial $ p(\lambda) $:
$$ p(\lambda) = -\lambda^3+13\lambda^2-55\lambda+75 $$Step 2 : Find the eigenvalues by solving the characteristic equation $ -\lambda^3+13\lambda^2-55\lambda+75 = 0. $
The eigenvalues are
$$ \lambda_1 = 3 ~ , ~ \lambda_2 = 5 ~ , ~ \lambda_3 = 5 $$( click here to view an explanation on how to solve this equation.)
Step 3 : To find the associated eigenvectors ( $ x $ ), we have to solve the equation $ A x = \lambda I $.
For $ \lambda_ 0 = 3 $ we have $ A x = 3 I $.
For $ \lambda_ 1 = 5 $ we have $ A x = 5 I $.
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