Question
Find eigenvectors of matrix:
$$ A = \left[ \begin{matrix}1&2&3\\0&2&3\\0&0&3\end{matrix} \right] $$Answer
The eigenvectors and eigenvalues of matrix A are:
| Eigenvalue | Eigenvector |
| $ 1 $ | $ \begin{bmatrix} 1 \cr 0 \cr 0 \end{bmatrix} $ |
| $ 2 $ | $ \begin{bmatrix} 1 \cr {{1}\over{2}} \cr 0 \end{bmatrix} $ |
| $ 3 $ | $ \begin{bmatrix} 1 \cr {{2 }\over{3}} \cr {{2}\over{9}} \end{bmatrix} $ |
Explanation
Step 1 : Find characteristic polynomial $ p(\lambda) $:
$$ p(\lambda) = -\lambda^3+6\lambda^2-11\lambda+6 $$Step 2 : Find the eigenvalues by solving the characteristic equation $ -\lambda^3+6\lambda^2-11\lambda+6 = 0. $
The eigenvalues are
$$ \lambda_1 = 1 ~ , ~ \lambda_2 = 2 ~ , ~ \lambda_3 = 3 $$( click here to view an explanation on how to solve this equation.)
Step 3 : To find the associated eigenvectors ( $ x $ ), we have to solve the equation $ A x = \lambda I $.
For $ \lambda_ 0 = 1 $ we have $ A x = 1 I $.
For $ \lambda_ 1 = 2 $ we have $ A x = 2 I $.
For $ \lambda_ 2 = 3 $ we have $ A x = 3 I $.
This page was created using
Eigenvectors calculator