Step 1: Determine the conjugate of the denominator. ( to find the conjugate just change the sign of the imaginary part ).

In this example, the conjugate of $ \color{orangered}{ 5-2i }\, $ is $ \color{blue}{ 5+2i } $.

Step 2: Multiply both the numerator and denominator by the conjugate:

$$\begin{aligned} \frac{ 6+3i }{ 5-2i } &= \frac{ 6+3i }{ 5-2i } \cdot \frac{ \color{blue}{ 5+2i } }{ \color{blue}{ 5+2i } } = \\[1 em] &= \frac{ \left( 6+3i \right) \cdot \left( 5+2i \right) }{ \left( 5-2i \right) \cdot \left( 5+2i \right) } \end{aligned} $$

Step 3: Simplify numerator and denominator (use $\color{blue}{i^2 = -1}$)

$$ \begin{aligned} \left( 6+3i \right) \cdot \left( 5+2i \right) &= 6 \cdot 5 + 6 \cdot \left(2 \,i \right) + \left( 3 \,i \right) \cdot \left(5 \right) + \left( 3 \,i \right) \cdot \left(2 \,i \right) = \\[1 em] &= 30 + 12 \, i + 15 \, i + 6 \color{blue}{(-1)} = \\[1 em] &= 24+27i\end{aligned} $$ $$ \begin{aligned} \left( 5-2i \right) \cdot \left( 5+2i \right) &= 5 \cdot 5 + 5 \cdot \left(2 \,i \right) + \left( -2 \,i \right) \cdot \left(5 \right) + \left( -2 \,i \right) \cdot \left(2 \,i \right) = \\[1 em] &= 25 + 10 \, i -10 \, i -4 \color{blue}{(-1)} = \\[1 em] &= 29\end{aligned} $$

Step 4: Separate real and imaginary parts:

$$ \frac{ 6+3i }{ 5-2i } = \frac{ 24+27i }{ 29 } = \frac{ 24 }{ 29 } + \frac{ 27 }{ 29 } i= \frac{ 24 }{ 29 }+\frac{ 27 }{ 29 }i $$

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