Step 1: Determine the conjugate of the denominator. ( to find the conjugate just change the sign of the imaginary part ).

In this example, the conjugate of $ \color{orangered}{ 3-2i }\, $ is $ \color{blue}{ 3+2i } $.

Step 2: Multiply both the numerator and denominator by the conjugate:

$$\begin{aligned} \frac{ 2+3i }{ 3-2i } &= \frac{ 2+3i }{ 3-2i } \cdot \frac{ \color{blue}{ 3+2i } }{ \color{blue}{ 3+2i } } = \\[1 em] &= \frac{ \left( 2+3i \right) \cdot \left( 3+2i \right) }{ \left( 3-2i \right) \cdot \left( 3+2i \right) } \end{aligned} $$

Step 3: Simplify numerator and denominator (use $\color{blue}{i^2 = -1}$)

$$ \begin{aligned} \left( 2+3i \right) \cdot \left( 3+2i \right) &= 2 \cdot 3 + 2 \cdot \left(2 \,i \right) + \left( 3 \,i \right) \cdot \left(3 \right) + \left( 3 \,i \right) \cdot \left(2 \,i \right) = \\[1 em] &= 6 + 4 \, i + 9 \, i + 6 \color{blue}{(-1)} = \\[1 em] &= 13i\end{aligned} $$ $$ \begin{aligned} \left( 3-2i \right) \cdot \left( 3+2i \right) &= 3 \cdot 3 + 3 \cdot \left(2 \,i \right) + \left( -2 \,i \right) \cdot \left(3 \right) + \left( -2 \,i \right) \cdot \left(2 \,i \right) = \\[1 em] &= 9 + 6 \, i -6 \, i -4 \color{blue}{(-1)} = \\[1 em] &= 13\end{aligned} $$

Step 4: Separate real and imaginary parts:

$$ \frac{ 2+3i }{ 3-2i } = \frac{ 13i }{ 13 } = \frac{ 0 }{ 13 } + \frac{ 13 }{ 13 } i= i $$

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