Find $ a_{ 100 } $ of an arithmetic progression if $ a_1 = 1 ~~ \text{and} ~~ d = 1 $.
To find $ a_{ 100 } $ we use formula
$$ \color{blue}{a_n = a_1 + (n-1)d}$$In this example we have $ a_1 = 1,~~ d = 1 ~~,~~ n = 100 $. After substituting these values into the formula, we obtain:
$$ \begin{aligned} a_n &= a_1 + d(n-1) \\[1 em] a_{ 100 } &= 1 + (100-1) \cdot 1 \\[1 em] a_{ 100 } &= 1 + 99 \\[1 em] a_{ 100 } &= 100 \end{aligned} $$The first few terms of this sequence are:
$$ 1, ~~~2, ~~~3, ~~~4, ~~~5 . . . $$