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• Tests on rationalizing denominator
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# Tests on rationalizing denominator

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Current: Rationalizing denominator with with one radical term
•  Q1: 1 pts Is the following computation correct? $$\frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}} {4}$$
 this is correct this is not correct
•  Q2: 1 pts What number we need to put instead ? to rationalize the denominator in: $$\frac{1}{\sqrt{5}} = \frac{1}{\sqrt{5}}\cdot\frac{?}{?}$$
 $? = \sqrt{15}$ $? = \sqrt{5}$ $? = \sqrt{25}$
•  Q3: 1 pts Rewrite $\frac{1}{\sqrt{3}}$ by rationalizing the denominator.
 $\frac{3}{\sqrt{3}}$ $3$ $\sqrt{3}$ $\frac{\sqrt{3}}{3}$
•  Q4: 1 pts Rationalize the denominator $\frac{14}{\sqrt{7}}$
 $\frac{14}{7\sqrt{7}}$ $2\sqrt{7}$ $14\sqrt{7}$
•  Q5: 2 pts Rationalize the denominator $$\sqrt{\frac{4}{5}}$$
 $\frac{2}{\sqrt{5}}$ $2\sqrt{5}$ $\frac{2\sqrt{5}}{5}$
•  Q6: 2 pts Simplify $$\frac{1}{\sqrt{12}}$$
 $\frac{\sqrt{3}}{6}$ $\frac{\sqrt{12}}{12}$ $12\sqrt{3}$
•  Q7: 2 pts Rationalize the denominator $$\sqrt{\frac{3}{6}}$$
 $\frac{\sqrt{18}}{6}$ $\frac{3\sqrt{6}}{6}$ $\frac{\sqrt{2}}{2}$
•  Q8: 3 pts Rationalize the denominator $$\frac{1}{\sqrt{x}}$$
 $\frac{\sqrt{x}}{x}$ $\sqrt{x}$ $x\sqrt{x}$
•  Q9: 3 pts Rationalize the denominator $$\frac{24}{\sqrt{3x}}$$
 $8\sqrt{3x}$ $\frac{24\sqrt{3x}}{3x}$ $\frac{8\sqrt{3x}}{x}$