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Tests on rationalizing denominator

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Current: Rationalizing denominator with with one radical term
  • Q1:
    1 pts
    Is the following computation correct? $$\frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}} {4}$$
    this is correct
    this is not correct
  • Q2:
    1 pts
    What number we need to put instead ? to rationalize the denominator in: $$ \frac{1}{\sqrt{5}} = \frac{1}{\sqrt{5}}\cdot\frac{?}{?}$$
    $? = \sqrt{15}$
    $? = \sqrt{5}$
    $? = \sqrt{25}$
  • Q3:
    1 pts
    Rewrite $\frac{1}{\sqrt{3}}$ by rationalizing the denominator.
    $\frac{3}{\sqrt{3}}$
    $3$
    $\sqrt{3}$
    $\frac{\sqrt{3}}{3}$
  • Q4:
    1 pts
    Rationalize the denominator $\frac{14}{\sqrt{7}}$
    $\frac{14}{7\sqrt{7}}$
    $2\sqrt{7}$
    $14\sqrt{7}$
  • Q5:
    2 pts
    Rationalize the denominator $$\sqrt{\frac{4}{5}}$$
    $\frac{2}{\sqrt{5}}$
    $2\sqrt{5}$
    $\frac{2\sqrt{5}}{5}$
  • Q6:
    2 pts
    Simplify $$\frac{1}{\sqrt{12}}$$
    $\frac{\sqrt{3}}{6}$
    $\frac{\sqrt{12}}{12}$
    $12\sqrt{3}$
  • Q7:
    2 pts
    Rationalize the denominator $$\sqrt{\frac{3}{6}}$$
    $\frac{\sqrt{18}}{6}$
    $\frac{3\sqrt{6}}{6}$
    $\frac{\sqrt{2}}{2}$
  • Q8:
    3 pts
    Rationalize the denominator $$\frac{1}{\sqrt{x}}$$
    $\frac{\sqrt{x}}{x}$
    $\sqrt{x}$
    $x\sqrt{x}$
  • Q9:
    3 pts
    Rationalize the denominator $$\frac{24}{\sqrt{3x}}$$
    $8\sqrt{3x}$
    $\frac{24\sqrt{3x}}{3x}$
    $\frac{8\sqrt{3x}}{x}$